-15x^2+37=0

Solution for -15x^2+37=0 equation:

-15x^2+37=0

a = -15; b = 0; c = +37;
Δ = b2-4ac
Δ = 02-4·(-15)·37
Δ = 2220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2220}=\sqrt{4*555}=\sqrt{4}*\sqrt{555}=2\sqrt{555}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{555}}{2*-15}=\frac{0-2\sqrt{555}}{-30}
=-\frac{2\sqrt{555}}{-30}
=-\frac{\sqrt{555}}{-15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{555}}{2*-15}=\frac{0+2\sqrt{555}}{-30}
=\frac{2\sqrt{555}}{-30}
=\frac{\sqrt{555}}{-15}
$